find directional cosines
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Step-by-step explanation:
Let α,β&γ are the angles of vector (5iˆ+2jˆ+6kˆ) from x, y and z-axis respectively.
then cosα=AxA=5∣∣5iˆ+2jˆ+6kˆ = 5/√65
cosβ=AyA=2∣∣5iˆ+2jˆ+6k^ = 2/√65
cosγ=AzA=6∣∣5iˆ+2jˆ+6kˆ = 6√65
The sum of squares of directional cosines of this vector
cos2α+cos2β+cos2γ=52+22+6265=6565=1
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