Math, asked by pravinmanibhaipatel, 9 months ago

find directional cosines​

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Answered by byaswanth2005
1

Answer:

\frac{5}{\sqrt{65} } ,\frac{2}{\sqrt{65} } ,\frac{6}{\sqrt{65} }

Step-by-step explanation:

Let α,β&γ are the angles of vector (5iˆ+2jˆ+6kˆ) from x, y and z-axis respectively.

then cosα=AxA=5∣∣5iˆ+2jˆ+6kˆ = 5/√65

cosβ=AyA=2∣∣5iˆ+2jˆ+6k^ = 2/√65

cosγ=AzA=6∣∣5iˆ+2jˆ+6kˆ = 6√65

The sum of squares of directional cosines of this vector

cos2α+cos2β+cos2γ=52+22+6265=6565=1

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