Question

Find discarimentof 2x2 +9=0

Answer 1

Answer:

$d = 6 \sqrt{2} i$

Explanation:

Given that:2x^2+9=0

To find :-Descariment(D)

$formula \: d = \sqrt{ {b}^{2} - 4ac}$

On comparing with standard quadratic equation

$a {x + bx }^{2} + c = 0$

We get,

Here a=2

b=0

c=9

Now putting these values in above formula

$d = \sqrt{ {0 }^{2} - 4 \times 2 \times 9} \\ \: \: \: = \sqrt{0 - 72 } \\ \: \: \: = \sqrt{ - 72} \\ \: \: \: = \sqrt{ - 2 \times 2 \times 3 \times 3 \times 2} \: \\ \: \: \: = 6 \sqrt{2} i$