Question

find discriminant and find nature of its roots x^+8x+16=0​

Answer 1

Answer:

real and equal roots.

Step-by-step explanation:

$Given \ quadratic \ equation, \\ x^2+8x+16=0 \\\\ it \ is \ of \ the \ form \ ax^2+bx+c=0 \\\\ a=1,b=8,c=16 \\\\ Discriminant,D=b^2-4ac \\\\ =>D=8^2-4(1)(16) \\ =>D=64-64 \\=>D=0 \\\\ it \ has \ real \ and \ equal \ roots.$

NATURE OF ROOTS :

If D < 0 ; no real roots

If D = 0 ; real and equal roots

If D > 0 ; real and unequal roots.

Answer 2

Answer:

x²+8x + 16

Here, a=1 , b=8 and c=16

we know that,

D= √b²-4ac

so, D=√8²-4.1.16

=√64-64= 0

Hence , roots are real and equal ( as b²-4ac=0)