find discriminant and nature of roots 2y²-6y=3
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Answer:
2-3-5
Step-by-step explanation:
2+6y=3
Hard
Solution
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The given quadratic equation 2y
2
+6y=3 which can be rewritten as 2y
2
+6y−3=0 is in the form ax
2
+bx+c=0 where a=2,b=6 and c=−3.
We know that the quadratic formula is x=
2a
−b±
b
2
−4ac
, therefore, substitute a=2,b=6 and c=−3 in x=
2a
−b±
b
2
−4ac
as follows:
x=
2a
−b±
b
2
−4ac
=
2×2
−6±
6
2
−(4×2×−3)
=
4
−6±
36+24
=
4
−6±
60
=
4
−6±
4×15
=
4
−6±2
15
=
4
2(−3±
15
)
=
2
−3±
15
Hence, x=
2
−3+
15
or x=
2
−3−
15
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