find discriminant d for quadratic equation 2x-4=-3/x and from that decide nature of its root
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Step-by-step explanation:
Given that,
2x - 4 = - 3/x
⇒ x ( 2x - 4 ) = - 3
⇒ 2x² - 4x = - 3
⇒ 2x² - 4x + 3 = 0
Comparing the given equation with ax²+ bx +c = 0,
we have a = 2 , b = - 4 and c = 3
∴Discriminant = d = b² - 4ac = ( - 4 )² - 4 ( 2) ( 3 ) = 16 - 24 = - 8.
There are no roots. Roots are imaginary.
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