Question

Find discriminant of
1)$x {}^{2} - 3 \sqrt{3 \: } x \: + 12 = 0$
2)
$5x {}^{2} - 6x - 2 = 0$

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Answer 1

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Answer 2

Step-by-step explanation:

Discriminant=>b²-4ac

(i) b=(-3√3),a=1,c=12

→(-3√3)²-4(1)(12)

→27-48

→(-21) that means it has no real roots.

(ii) b=(-6), a=5,c=(-2)

→(-6)²-4(5)(-2)

→36+40

→76 that means different real roots exists.

Hope this answer helps you...