find discriminant of 6x^2-13x+6=0
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Answered by
2
D=b^2-4ac
D=(-13)^2-4*6*6
D=169-144
D=25
Therefore it has real and unequal roots.
D=(-13)^2-4*6*6
D=169-144
D=25
Therefore it has real and unequal roots.
Answered by
2
Given Equation is 6x^2 - 13x + 6 = 0
Where a = 6,b=-13,c = 6.
We know that D = b^2 - 4 * a * c
= (-13)^2 - 4(6)(6)
= 169 - 144
= 25.
Therefore the discriminant = 25.
Hope this helps!
Where a = 6,b=-13,c = 6.
We know that D = b^2 - 4 * a * c
= (-13)^2 - 4(6)(6)
= 169 - 144
= 25.
Therefore the discriminant = 25.
Hope this helps!
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