Find discriminant of px^2-(p+q)x +q = 0
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Answer:
p^2 + q^2 - 2pq
Step-by-step explanation:
Discriminant is equal to (b^2-4 a*c) for the equation ;- a*x^2+b*x+c=0
so here in the equation px^2-(p+q)x +q = 0,
a=p, b= -(p+q) and c= q
therefore discriminant here is (-(p+p))^2 - 4*p*q
= p^2 + q^2 + 2pq -4pq
=p^2 + q^2 - 2pq
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