Question

find discriminant of quadratic equation 5x^2+2x+1/5=​

Answer 1

Answer:

answer - 0

Step-by-step explanation:

a=5

b=2

c=1/5

D = b^2 - 4ac

D = 2^2 - 4 * 5 * 1/5

D = 4 - 20 * 1/5

D = 4 - 4

D = 0

Answer 2

Answer:

Discriminant = 0

Step-by-step explanation:

We know that,

If ax² + bx + c is a Quadratic equation then,

Discriminant = b² - 4ac

Here,

5x² + 2x + (1/5) = 0

Multiplying the whole equation by 5 we get,

25x² + 10x + 1 = 0

ax² + bx + c = 0

where a = 25, b = 10, c = 1

D = b² - 4ac

D = 10² - 4(25)(1)

D = 100 - 100

D = 0

Thus, the Discriminant of the Quadratic equation 5x² + 2x + (1/5) = 0

Just for your information,

The Discriminant determines the roots of the Quadratic equation,

If D = 0

then, they have real and equal roots

Hope it helped and you understood it........All the best