Question

Find discriminant of quadratic equation and hence comment upon nature of roots of equation

x

2

+√2 x + 4=0.​

Answer 1

Answer:

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Step-by-step explanation:

ERROR IN SUBTRACTION

Answer 2

➲APPROPRIATE QUESTION :

• Find discriminant of quadratic equation and hence comment upon nature of roots of equation $: \sf{x^2 + \sqrt{2} x+4= 0}$

☯ GIVEN :

• $\bf{x^2 + \sqrt{2} x+4 = 0}$

☯TO FIND :

• The discriminant and nature of the roots.

☯ FORMULA REQUIRED :

• $\bigstar{\underline{\boxed {\red{\bf{D= b^2 -4ac}}}}}$

➲SOLUTION:-

✞ We have,

• a = 1

• b = $\bf {\sqrt{2} }$

• c = 4

Substituting the given values :

$\leadsto {\tt{D= b^2 - 4ac}}$

$\leadsto {\tt{D= ( \sqrt{2})^2 - 4\times 1\times 4 }}$

$\leadsto {\tt{D=2 - 16}}$

$\leadsto{\underline{ \huge{\green{\boxed{ \bf{D =-14}}}}}}$

$\huge{ \pink{\therefore}}$ Here , D is smaller than 0 so roots are unreal and imaginary .