Question

find discriminant of the quadratic equation : √3x2–10x+ 4√3

Answer 1

$Discriminant = {b}^{2} - 4ac \\ = {( -10)}^{2} - 4 \times \sqrt{3} \times 4 \sqrt{3} \\ = 100 - 16 \times 3 = 100 - 48 = 52$

So, Discriminant of the given equation is 52

Answer 2

Answer:

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