Question

find discriminant of the quadratic equation and write nature of root.
${x}^{2} - 7x + 12 = 0\ \textless \ br /\ \textgreater$
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Answer 1

Answer:

$discriminant \: = {b}^{2} - 4ac \\ = {( -7 )}^{2} - 4 \times 1 \times 12 \\ \ = 49 - 48 \\ = 1$

Since D > 0, so equation has distinct and real roots.

Answer 2

Answer:

discrinant=b^2-4ac

(7)^2- 4×1×12

49-48=1

mark as brainliest

so nature of the roots is real and unequal