Find displacement if time is 3.14sec and acceleration is 9.8m/s
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Answer:
48.31 m
Explanation:
S=ut + (1/2)a*t²
s= (0×3.14) + (1/2)9.8×(3.14²)
s= 0 + (1/2)9.8×(3.14²)
s= 48.31
s=displacement
u=initial velocity
t=time
a=acceleration
generally with questions like this we need either initial or final velocity.
And if not given we assume INITIAL VELOCITY (u)= 0.
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