Physics, asked by dikshesh4762, 1 year ago

Find displacement if time is 3.14sec and acceleration is 9.8m/s

Answers

Answered by himanshu9a20
0

Answer:

48.31 m

Explanation:

S=ut + (1/2)a*t²

s= (0×3.14) + (1/2)9.8×(3.14²)

s= 0 + (1/2)9.8×(3.14²)

s= 48.31

s=displacement

u=initial velocity

t=time

a=acceleration

generally with questions like this we need either initial or final velocity.

And if not given we assume INITIAL VELOCITY (u)= 0.

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