find displacement of the particle when v=3t^2-2t from t= 0s to t=2s [hint:- do integration and put t=0 as lower limit & t=2s as upper limit ]
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1
Answer:
4m
Step-by-step explanation:
First According to the hint we integrate both sides
so we will get
x = t^3 - t^2
by putting the upper limit, we get
x = 8 - 4
= 4
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