Question

find distance between 1)(5,3)and(3,2) 2)(-1,4)and(2,-3). 3)(a-b)and(-b,a)​

Answer 1

Answer:

Distance formula :-

d = √[(x2-x1)²+(y2-y1)²]

1)(5,3) and (3,2)

d = √[(3-5)²+(2-3)²]

= √(4+1)

= √5 units

2) (-1,4) and (2,-3)

d = √[(2+1)²+(-3-4)²]

= √(9+49)

= √58units

3) (a,-b) and (-b,a)

d = √[(-b-a)²+(a+b)²]

= √[(b+a)²+(a+b)²]

= √(2(a+b)²)

= √2 (a+b) units