Question

Find distance between (2,5)
(-3,-2)​

Answer 1

Given point

$\sf \to \: P(2,5) \: \: \: and \: \: \: Q(-3,-2)$

To find Distance between PQ

Formula

$\sf \to \: PQ = \sqrt{(x_2 - x_1) {}^{2} + (y_2 - y_1) {}^{2} }$

By comparing with

$\sf \to \:P(x_1,y_1) \: and \: Q = (x_2 ,y_2)$

We get

$\sf \to (x_1 = 2,y_1 = 5) and (x_2 = - 3 ,y_2 = - 2)$

Put the value on formula

$\sf \to \: PQ = \sqrt{( - 3 - 2) {}^{2} + ( - 2- 5) {}^{2} }$

$\sf \to \: PQ = \sqrt{( - 5) {}^{2} + ( - 7) {}^{2} }$

$\sf \to \: PQ = \sqrt{25 + 49}$

$\sf \to \: PQ = \sqrt{74}$

Distance Between PQ Is√(74) units