find distance between 8x+6y-11=0,4x+3y-6=0
Answers
Answered by
1
Answer:
Step-by-step explanation:
Given lines are 4x + 3y = 11 and 4x + 3y = \frac{15}{2}
2
15
Distane between two parallel lines
|c₁ - c₂ / √a² + b²|
= | 11 - \frac{15}{2}
2
15
/ √16 + 9 |
= | 7 / 2 × 5 |
= \frac{7}{10}
10
7
Good luck !!
Answered by
0
Answer:
7/10
Step-by-step explanation:
4x+3y=11 (i)
8x+6y=15
4x+3y=15/2 (ii)
slope of line =-4/3
slope of line=-4/3
since the slope are equal the lines are parallel
Distance between two parallel lines
|(c1 -c2)|/√( a2+b2)
=| (11-15/2)|/√(42+32/)
= 7/10
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