Math, asked by meetkumar34, 5 months ago

find distance between 8x+6y-11=0,4x+3y-6=0​

Answers

Answered by qayamuddin
1

Answer:

Step-by-step explanation:

Given lines are 4x + 3y = 11 and 4x + 3y = \frac{15}{2}

2

15

Distane between two parallel lines

|c₁ - c₂ / √a² + b²|

= | 11 - \frac{15}{2}

2

15

/ √16 + 9 |

= | 7 / 2 × 5 |

= \frac{7}{10}

10

7

Good luck !!

Answered by sushmithamurali2106
0

Answer:

7/10

Step-by-step explanation:

4x+3y=11 (i)

8x+6y=15

4x+3y=15/2 (ii)

slope of line =-4/3

slope of line=-4/3

since the slope are equal the lines are parallel

Distance between two parallel lines

|(c1 -c2)|/√( a2+b2)

=| (11-15/2)|/√(42+32/)

= 7/10

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