Question

find distance between points (-2, 3) and (4, 5) ​

Answer 1

Answer:

See this number line in this positive number are in right side and negative number are in left side so the distance between -2 and 3 is of 3 numbers -1, 0 and 1 and your second question 4 and 5 difference is no difference because they are in same side and one after the other

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Answer 2

$Let \: A(-2,3) = ( x_{1},y_{1}) \:and$

$B(4,5) = ( x_{2},y_{2})$

$Distance \: AB = \sqrt{ (x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2} }$

$= \sqrt{ [4-(-2)]^{2} + ( 5-3)^{2} }$

$= \sqrt{ (4+2)^{2} + 2^{2} }$

$= \sqrt{ 36 + 4 }$

$= \sqrt{40}$

$= 2\sqrt{10}$

Therefore.,

$\red{ Distance }\green { = 2\sqrt{10} }$

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