Question

find distance between points p(b+c,c+a), q(c+a,a+b) ​

Answer 1

Answer:

√{a^2 - c^2 -2ab + 2bc}

Step-by-step explanation:

P( b+c , c+a ) . Q( c+a, a+b)

Using distance formula

$\sqrt{{(x2 - x1)}^{2} - {(y2 - y1)}^{2} }$

here x2 = c+a

x1 = b+c

y2 = a+b

y1 = c+a

Distance =

$\sqrt{ {(c + a - b - c)}^{2} - {(a + b - c - a)}^{?} }$

$\sqrt{ {(a - b)}^{2} - {(b - c)}^{2} }$

$\sqrt{ {a}^{2} + {b}^{2} - 2ab - {b}^{2} - {c}^{2} + 2bc }$

$\sqrt{ {a}^{2} - {c}^{2} - 2ab + 2bc }$

here is your distance .

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