Find distance between (sin90,cos0)(tan45,cot45)
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√2
Step-by-step explanation:
Given.,
Point 1 = ( Sin 90, Cos 90 ) = ( 1,0 )
Point 2 = ( Tan 45, Cot 45 ) = ( 1,1 )
Now, Distance B/w two points is
=> √((( 1 - 1 )^2 ) + (( 1 - 0 )^2))
=> √( 1 + 1 )
=> √2
So Answer is √2
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