Question

Find distance between the lines 3x-4y=5 and 6x-8y= 12​

Answer 1

Answer:

1/5

Step-by-step explanation:

given lines are 3x-4y-5=0••••(1)

6x-8y-12=0

2(3x-4y-6)=0

3x-4y-6=0••••(2)

the distance between two lines is

$d = \frac{ |c1 - c2| }{\sqrt{ {a}^{2} + {b}^{2} } }$

$d = \frac{ | - 5 - ( - 6)| }{ \sqrt{ {3}^{2} + { ( - 4)}^{2} } }$

d=1/5