Question

find distance between the points
(8,-3) and (0,9)​

Answer 1

Answer:

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Answer 2

To find the distance between the points (8, -3) and (0, 9).

A( 8, -3); B(0, 9).

Distance formula:

$\tt \sqrt{\bigg[\bigg(x_2\ -\ x_1\bigg)^2\ +\ \bigg(y_2\ -\ y_1\bigg)^2\bigg]}$

From the given points,

$\tt x_1\ =\ 8\\\\x_2\ =\ 0\\\\y_1\ =\ -3\\\\y_2\ =\ 9$

Substituting these values in the formula,

$\tt =\ \sqrt{\bigg[\bigg(0\ -\ 8\bigg)^2\ +\ \bigg(9\ +\ 3\bigg)^2\bigg]}\\\\\\\\=\ \sqrt{\bigg[\bigg(- 8\bigg)^2\ +\ \bigg(12\bigg)^2\bigg]}\\\\\\\\=\ \sqrt{\bigg[64\ +\ 144\bigg]}\\\\\\=\ \sqrt{208}\ units.$

Therefore, the distance between the points (8, -3) and (0, 9) is √208 units.