Find distance of point ( 3,-5) from line 3x-4y-26=0
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Answered by
4
Answer:
3/5
Step-by-step explanation:
Line is 3x - 4y - 26 = 0.
Comparing with Ax + By + C = 0, we get
A = 3, B = -4, C = -26.
Point is (3,-5).
x₁ = 3, y₁ = -5
The distance of the point P(x₁,y₁) to ax + by + c = 0 is
d = |Ax₁ + By₁ + C/√A² + B²|
= |3(3) + (-4)(-5) + (-26)/√(3)² + (-4)²
= |9 + 20 - 26|/√25|
= 3/5
Hence, the distance = 3/5
Hope it helps you
#Bebrainly
Answered by
1
line is :
→ 3x-4y-26=0.....( 1 )
comparing with Ax+ßy+c=0
A=3
ß=(-4)
c=(-26)
point is (3,-5)
x1=3,y1=(-5)
↪the distance of point P (x1,y1) to Ax+say+c=0 is⤵⤵
distance is
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