find distance of the plane 2x-3y+4z-6=0 from the origin
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6/√2^2+3^2+4^2 =6/√29
cabirbansal91p6edgf:
how it is solved tell me ?
distance between origin and a line is |2*0-3*0+4*0-6|/√2^2+3^2+4^2
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