Math, asked by cabirbansal91p6edgf, 1 year ago

find distance of the plane 2x-3y+4z-6=0 from the origin

Answers

Answered by shreyaboyini309

2

6/√2^2+3^2+4^2 =6/√29

cabirbansal91p6edgf: how it is solved tell me ?

shreyaboyini309: distance between origin and a line is |2*0-3*0+4*0-6|/√2^2+3^2+4^2

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