find domain and range: 1/√(16-x²)
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Answer:
Range [0,4]
Step-by-step explanation:
Consider the given function.
f(x)= √ 16−x²
For domain under root should not be negative quantity,
16−x²≥0
16≥x²
Therefore,
x≤4 or x≥ −4
Then,
The domain[−4,4]
Range: f(x) is maximum at x=0,f(x)=4
And f(x) is minimum at x=4,f(x)=0
Range
[0,4]
Hence, this is the answer.
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