Question

find domain and range: 1/√(16-x²)
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Answer 1

Answer:

Range [0,4]

Step-by-step explanation:

Consider the given function.

f(x)= √ 16−x²

 

For domain under root should not be negative quantity,

16−x²≥0

16≥x²

Therefore,

x≤4 or x≥ −4

Then,

 The domain[−4,4]

Range: f(x) is maximum at x=0,f(x)=4

And f(x) is minimum at x=4,f(x)=0

Range

[0,4]

Hence, this is the answer.