Question

find domain and range

f(X)=1/{sqrt(5)-x}

Answer 1

Answer:

x < √5 (or) x > √5.

(-∞,√5) ∪ (√5, ∞)

Step-by-step explanation:

∴ Domain of a function is the set of argument values for which the function is real and defined.

Given: f(x) = 1/{(√5) - x}

⇒ √5 - x = 0

⇒ √5 = x

Therefore,

Domain: x < √5 (or) x > √5.

Range: (-∞, √5) ∪ (√5,∞).

Hope it helps!