Question

find domain and range of 1/(2x-3)(x+1)
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Answer 1

Answer:

domain real numbers minus -1 and 1.5

and range the value that comes when we domin in given equation

Answer 2

Answer:

\frac{1}{-x^{2}-x}

Step-by-step explanation:

\frac{ 1 }{ (2x-3x)(x+1) }

Combine 2x and -3x to get -x.

\frac{1}{-x\left(x+1\right)}

Use the distributive property to multiply -x by x+1.

\frac{1}{-x^{2}-x}

Hope this helps you