Question

Find domain and range of f(x)=1/3 x^5

Answer 1

Step-by-step explanation:

Domain

x can't be zero.

Range

Domain of inverse function is range

$y = \frac{1}{3 {x}^{5} } \\ x = \sqrt[5]{ \frac{1}{3y} }$

So again range is y non zero .

Note : Taking root take care of negative signs