Find domain and range of F(x)=√9-x^2
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values of x will be restricted such that ( 9 - x^2 ) > 0
9 - x^2 = ( 3 + x ) ( 3 - x )
this is parabola of inverted U shape, whose value is +ve in between roots.
so ( 9 - x^2 ) > 0 for x in between -3 & 3
so domain is x = [ -3 , 3 ]
range = ( 0 , max of f(x) )
f(x) is maximum at mid point of roots, i.e. f max = f(0) = 3
so range = ( 0 , 3 )
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