find domain and range of f(x)=√9-xsquare
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Answer:
First we should define the function in interval.
Since there is square root,
9−x2>=0
(3+x)(3−x)>=0
(3+x)(x−3)<=0
Therefore x is defined over [-3,3]
This is the domain of function.
For range,
Y2=9−x2
X2=9−y2
Since x is only real
Discreminant of 9−y2is>=0
Now do the math and get the range.
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