Math, asked by abhayjaiswal2101, 1 year ago


. Find domain and range of real function f(x) = √9- x^2

Answers

Answered by rahman786khalilu
6

Domain is[ -3,3] Range is [0,3]

Answered by Anonymous
9

Answer:

Step-by-step explanation:

√(9-x^2) , so the value present in the sq root of any number is always (+).

ex:√9=3, 9 is (+)

so to proceed,

9-x^2<=0

so,

x^2=9 so x=-3 or 3

domain is (x)=-3,3

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