Question

find
domain and range of relation
R= {x, y): x²+ y^2=25 , where x,y belong to z?​

Answer 1

Answer:

R={(0,5),(0,−5),(3,4),(−3,4),(3,−4),(−3,−4),(4,3),(−4,3),(4,−3),(−4,3),(5,0),(−5,0)}

R

−1

={(5,0),(−5,0),(4,3),(4,−3),(−4,3),(−4,−3),(3,4),(3,−4),(−3,4),(3,−4),(0,5),(0,−5)}

Therefore domain of R≡{0,3,−3,−4,4,−5,−5}= domain of R

−1

Step-by-step explanation:

please follow

Answer 2

Answer:

step-by-step explanation

Step-by-step explanation:

We have, R = {(x,y):x,y∈ W, x2 + y2 = 25}

= {(0,5), (3,4), (4, 3), (5,0)}

Domain of R = Set of first element of ordered pairs in R = {0,3,4, 5}

Range of R = Set of second element of ordered pairs in R = {5,4, 3, 0}