find domain of f(x)=x+4/x^2-9
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Answer:
R-{+3,-3}
Step-by-step explanation:
The domain of a function y = f(x) is the set of values that x can take on for which y is real and defined.
For the given function f(x) = (x+4)/(x^2 - 9) , the value of f(x) is defined in all cases where the value of the denominator is not zero. The value of any fraction where the denominator is 0 is not defined.
If x^2 - 9 = 0
x^2 = 9
x = +- 3
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