Math, asked by n3603808, 4 months ago

find domain of f(x)=x+4/x^2-9​

Answers

Answered by oshanchakraborty
0

Answer:

R-{+3,-3}

Step-by-step explanation:

The domain of a function y = f(x) is the set of values that x can take on for which y is real and defined.

For the given function f(x) = (x+4)/(x^2 - 9) , the value of f(x) is defined in all cases where the value of the denominator is not zero. The value of any fraction where the denominator is 0 is not defined.

If x^2 - 9 = 0

x^2 = 9

x = +- 3

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