Question

find domain of function is defined by f(x)=1/x^2+8x+12
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Answer 1

Answer:

The domain of the function is R - {0}.

Answer 2

SOLUTION ⚜️

$given \: f(x) = \frac{ {x}^{2} + 2x + 1 }{ {x}^{2} - 8x + 12}$

Here, f(x) is an rational function of x as$\frac{ {x}^{2} + 2x + 1 }{ {x}^{2} - 8x + 12}$is rational expression.

$\therefore f(x) \: assumes \: real \: values \: x \: espects \\ for \: the \: values \: of \: x \: for \: which \: {x}^{2} - 8x + 12 = 0$

$i.e.,(x - 6)(x - 2) = 0 \rightarrow x = 6,2 \\ \therefore domain \: of \: f(x)$

= R-{2,6}