Math, asked by question0016468, 11 months ago

Find domain of the function
f(x) =  \frac{{x}^{2}  + 3x + 5}{ {x}^{2}  - 5x + 4}


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Answers

Answered by sprao534
1

Domain of f(x) is R-{1,4}


question0016468: how?
question0016468: please explain
sprao534: f(x) is real valued function if denominator is not equal to 0. denominator is equal to 0 for x= 1,4. so domain is all real numbers except 1,4. Domain =R - {1,4}
Answered by siddhartharao77
2

Answer:

x ≠ 4, x ≠ 1

Step-by-step explanation:

Method - 1:

Given: f(x) = (x² + 3x + 5)/(x² - 5x + 4)

For the domain, the denominator must be ≠ 0.

Since we cannot have a zero in the denominator, we will first find out which numbers make the denominator zero.

Set up the equation to solve for x:

⇒ x² - 5x + 4 = 0

⇒ x² - 4x - x + 4 = 0

⇒ x(x - 4) - (x - 4) = 0

⇒ (x - 1)(x - 4) = 0

⇒ x = 1, 4

Excluding these values from the domain, we get x ≠ 4, x≠ 1.

Domain : (-∞,1) ∪ (1,4) ∪ (4,∞), {x|x ≠ 1,4} for any integer n

Range: (-∞,∞), {y|y ∈ R}.

Hope it helps!


Anonymous: Sir, if we use ' not equal to' sign while solving the equation. Then, will it be ok or wrong?
siddhartharao77: Depends on the question!
question0016468: Siddharth bhai rocks everywhere
siddhartharao77: Thank you
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