Question

find domain please answer me​

Answer 1

x2 -3x + 2 = (x - 2)(x - 1) is not = 0

x is not = 1,2  SO, Domain = R -{1,2}

Let the function f(x) = y  

therefore, 2x - 3 = x2y - 3xy + 2y

            ,  x2y + x(2 - y) + (2y + 3) = 0

              x = y -2 +-{ [(2 - y)2 - 4y(2y + 3)]1/2 }/2y

           y is not = o  

            4 + y2 - 4y - 8y2 - 12y > 0

           7y2 + 16y - 4 < 0

           now solve for y and take out the range  

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Answer 2

Answer:

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Step-by-step explanation:

x2 -3x + 2 = (x - 2)(x - 1) is not = 0

x is not = 1,2  SO, Domain = R -{1,2}

Let the function f(x) = y  

therefore, 2x - 3 = x2y - 3xy + 2y ,  x2y + x(2 - y) + (2y + 3) = 0

x = y -2 +-{ [(2 - y)2 - 4y(2y + 3)]1/2 }/2y  

4 + y2 - 4y - 8y2 - 12y > 0

7y2 + 16y - 4 < 0