Question

Find domainand range of square root of x^2-9

Answer 1

Answer

x≤−3 or x≥3

y∈R,y≥0

Explanation:

for the domain we require

x2−9≥0

⇒x2≥9

⇒x≤−3 or x≥3

domain is (−∞,−3]∪[3,+∞)

range is y∈R,y≥0

graph{sqrt(x^2-9) [-10, 10, -5, 5]}

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