Math, asked by mmanojjoshi452, 1 month ago

Find
dx
dy y
when y = log (log (sinx))​

Answers

Answered by atharvarangdale
0

Step-by-step explanation:

y= log(log(sinx))

dy/dx = 1/log(sinx) × d/dx log(sinx)

= cosx / log(sinx) × (sinx)

= cosx / log(sin²x)

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