Question

Find Dx for 3x + 4y afh, 2x+ 5y = 16.​

Answer 1

Answer:

$4\frac{2}{13}$

Step-by-step explanation:

$2x+5y=16\\\\\\5y=16-2x\\\\\\y=\frac{16-2x}{5}$

So,

$3x+4y=14\\\\\\\frac{3x}{1}+\frac{16-2x}{5}=14\\\\\\\frac{15x+(16-2x)}{5}=14\\\\\\\frac{15x+16-2x}{5}=14\\\\\\15x-2x+16=5*14\\\\\\13x+16=70\\\\\\13x=70-16\\\\\\13x = 54\\\\\\x=\frac{54}{13}\\\\\\x=4\frac{2}{13}$

Answer 2

Step-by-step explanation:

=>Given:

. 3x+4y=14.....(1)

. 2x+5y=16.....(2)

=>to find ;

. Value of x-y

=>solution

=>multiplying (1)with2 & (2)with

3 we get

=6x+8y=28 & 6x+10y=32

Now subtracting new (1) with (2)

. 6x +10y=32

.-6x - 8y=-28

_______________

2y=4

_______________

=Y=4/2

Using this value of y in (1)

=3x+4*2=14

=>3x=6

X=2

Value of x - y

=x-y=0