Question

FIND dy by dx of   x²+xy+y² =1

Answer 1

x² + x y + y² = 1
Take Differentials on both sides , we get
   2 x  dx + ( x dy + y dx ) + 2y  dy  =  0

So     (2 x + y )  dx  + (x + 2 y) dy   =  0

          d y / d x  =  (2 x + y ) / (x + 2y)

Answer 2

this is dy/dx=2x+y+0-0 dy/dx=2x+y