find dy by dx where cos (sinx)
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solution:- let y = cos(sinx)
dy/dx = d{cos(sinx)/dx
using chain rule
dy/dx = d{cos(sinx)/d(sinx)/ d(sinx)dx.
= -sin(sinx) *cosx
= - sin(sinx)*cosx Answer
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Hope it's helpful
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Step-by-step explanation:
refer to this attachment ✅✅
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