find dy/dt if y=cos(5-3t)
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y = cos (5 - 3t)
Differentiating both sides w.r.t. t, we get
dy/dt = d [ cos(5 - 3t) ] / dt
differentiation of cos x is = - sin x
So,
dy/dt = - sin (5 - 3t) X (-3)
[ differentiation of (5 - 3t) is -3], so we apply chain rule]
dy/dt = 3 sin (5 - 3t)
Differentiating both sides w.r.t. t, we get
dy/dt = d [ cos(5 - 3t) ] / dt
differentiation of cos x is = - sin x
So,
dy/dt = - sin (5 - 3t) X (-3)
[ differentiation of (5 - 3t) is -3], so we apply chain rule]
dy/dt = 3 sin (5 - 3t)
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