Question

find dy/dt

y=(ax+b)^2​

Answer 1

Answer:

given that y = (ax+b)^2.

dy/dx = 2 (ax+b).

I hope this may helps you.

Answer 2

Step-by-step explanation:

$y = {(ax + b)}^{2} \\ \frac{dy}{dx} = 2(ax + b) \times \frac{d(ax + b)}{dx} \\ = 2a(ax + b) \\ using \: chain \: rule$

hope this helps ....