Question

Find dy/dx (1+2x) (1+4x²)
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Answer 1

Step-by-step explanation:

tan−1(1−2x1+2x)1+(1−2x1+2x)21[(1−2x)2(1−2x)(2)−(1+2x)(−2)](1+2x)2+(1−2x)2(1−2x)2[(1−2x)22−4x+2+4x]1+4x2+4x+1+4x2−4x4=2(1+4x2)4=1+4x22dxd(1+4x2)=21+4x21

Answer 2

Answer:

Answer is

$\frac{ - 8x {}^{2} - 8x + 2}{(1 + 4x {}^{2}){}^{2} }$

Step-by-step explanation:

Explanation in attachment: