Question

Find dy/dx 2sinxcosx + tany = 2x

Answer 1

Answer:

2cos2x+sec²x-2=0

PLZ:

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Step-by-step explanation:

d(tanx)/dx=sec²x

d(sinxcosx)/dx=d(sinx)/dxcosx+d(cosx)/dxsinx

                       {applying uv rule ↑}

                        =cosx(cosx)+(-sinx)sinx

                        =cos²x-sin²x

                        =cos2x

d(2x)/dx=2

dy/dx

2(cos2x)+sec²x=2

2cos2x+sec²x-2=0