. Find dy/dx: 2x+3y= Sin x *
1 point
(Cos x-2)/3
(Cos x+2)/3
(Sin x-2)/3
None of these
Answers
Answered by
0
Differentiation of implicit function :
2x+3y = sinx
differentiating with to x
=2 + 3dy/dx = cosx { dy/dx(cosx) =1
=3dy/dx = cosx-2
=dy/dx = (cosx-2)/3
Therefore 1st option is the right answer...
Answered by
5
ANSWER :–
dy/dx = [cos(x) - 2]/3
EXPLANATION :–
GIVEN :–
A function 2x + 3y= sin(x).
TO FIND :–
dy/dx
SOLUTION :–
• According to the question –
=> 2x + 3y= sin(x)
• Differentiate with respect to 'x' –
=> 2 + 3 (dy/dx) = cos(x)
=> 3 (dy/dx) = cos(x) - 2
=> dy/dx = [cos(x) - 2]/3
● Hence , first option is correct.
USED FORMULA :–
(1) d[sin(x)]/dx = cos(x)
sethrollins13:
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