Question

find dy/dx as a function of x using chain rule. y= √(3x^2-4x+6)

Answer 1

Step-by-step explanation:

We have,

$y = \sqrt{ 3{x}^{2} - 4x + 6 }$

$= > \frac{dy}{dx} = \frac{6x - 4}{2 \sqrt{3 {x}^{2} - 4x + 6 } }$

$= > \frac{dy}{dx} = \frac{3x - 2}{ \sqrt{3 {x}^{2} - 4x + 6} }$