Question

Find dy/dx for the following
sin( sqrt 1+cos x

Answer 1

Answer:

Step-by-step explanation:

y = sin($\sqrt{1+cosx}$)

dy/dx = d(sin($\sqrt{1+cos\\x}$))/dx  d(($\sqrt{1+cosx}$))/dx

= cos($\sqrt{1+cosx}$) (1/2)(1+cos x)^(-1/2) (-sinx)

= (-sinx cos($\sqrt{1+cox}$)) / (2 $\sqrt{1+cosx}$)