Question

find dy/dx for √xsinx cosx​

Answer 1

Answer:

ANSWER :-

GIVEN EQUATION -

$y = \sqrt{x}. sinx.cosx$

WE SHOULD WRITE THIS AS -

$y = \sqrt{x} ( \frac{1}{2} )(sin2x)$

NOW D.W.R. TO 'X' -

$\frac{dy}{dx} = \frac{1}{2} ( \sqrt{x} \times cos(2x) \times 2 + sin(2x) \times \frac{1}{2 \sqrt{x} } )$

$\frac{dy}{dx} = \sqrt{x} cos2x + \frac{1}{4 \sqrt{x} } sin2x$