Physics, asked by divyakshi0910, 11 months ago

find dy/dx for y=1+3x-x^2​

Answers

Answered by Crystall91
1

y = 1+3x-x²

dy/dx = d(1+3x-x²)/dx

=>d1/dx + d3x/dx + d-x²/dx

=>0 + 3x¹-¹ -2x²-¹

=>3-2x

Therefore dy/dx = 3-2x

Cheers!

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