find dy/dx for y=1+3x-x^2
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y = 1+3x-x²
dy/dx = d(1+3x-x²)/dx
=>d1/dx + d3x/dx + d-x²/dx
=>0 + 3x¹-¹ -2x²-¹
=>3-2x
Therefore dy/dx = 3-2x
Cheers!
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